Balance the following equation by oxidation number method:
$S + O H^{-} \to S^{2 -} + S_{2} O_{3}^{2 -}$ .

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Solution

$0 S \to S^{2 -}$ (decrease of $2$ )
$2 0 S \to S_{2} O_{3}^{2 -}$ (increase of $2$ per S atom).
$4 S + 6 O H^{-} \to 2 S^{2 -} + S_{2} O_{3}^{2 -} + 3 H_{2} O$

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