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Question

Balance the following equation by the oxidation number method.
Cr(S)+Pb(NO3)2(aq)Cr(NO3)3(aq)+Pb(S)

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Solution

Cr(s)+Pb(NO3)2(aq)Cr(NO3)3(aq)+Pb(s)
0Cr(s)3+Cr(aq)+3e(1)
Pb2+(aq)+2ePb0(s)(2)
Now Multiplying equation (1) by 2 and multiplying equation (2) by 3 followed by adding will give :
2Cr0(s)2Cr3+
3Pb2+3Pb0(s)–––––––––––––––––––
2Cr(s)+3Pb2+=2Cr3++3Pb
or, 2Cr(s)+3Pb(NO3)2(aq)=2Cr(NO3)2(aq)+3Pb(s)

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