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Byju's Answer
Standard XII
Chemistry
Oxidation Number Method
Balance the f...
Question
Balance the following equation by the oxidation number method.
C
r
(
S
)
+
P
b
(
N
O
3
)
2
(
a
q
)
→
C
r
(
N
O
3
)
3
(
a
q
)
+
P
b
(
S
)
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Solution
C
r
(
s
)
+
P
b
(
N
O
3
)
2
(
a
q
)
⟶
C
r
(
N
O
3
)
3
(
a
q
)
+
P
b
(
s
)
0
C
r
(
s
)
⟶
3
+
C
r
(
a
q
)
+
3
e
−
⟶
(
1
)
P
b
2
+
(
a
q
)
+
2
e
−
⟶
P
b
0
(
s
)
⟶
(
2
)
Now Multiplying equation
(
1
)
by
2
and multiplying equation
(
2
)
by
3
followed by adding will give :
2
C
r
0
(
s
)
⟶
2
C
r
3
+
3
P
b
2
+
⟶
3
P
b
0
(
s
)
–
–––––––––––––––––––
–
2
C
r
(
s
)
+
3
P
b
2
+
=
2
C
r
3
+
+
3
P
b
or,
2
C
r
(
s
)
+
3
P
b
(
N
O
3
)
2
(
a
q
)
=
2
C
r
(
N
O
3
)
2
(
a
q
)
+
3
P
b
(
s
)
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1
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