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Oxidation Number Method

Balance the f...

Question

Balance the following equation by the oxidation number method.
$C r_{(S)} + P b (N O_{3})_{2 (a q)} \to C r (N O_{3})_{3 (a q)} + P b_{(S)}$

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Solution

${C r}_{(s)} + {P b {({N O}_{3})}_{2}}_{(a q)} ⟶ {C r {({N O}_{3})}_{3}}_{(a q)} + {P b}_{(s)}$
$0 C r (s) ⟶ 3 + C r (a q) + 3 e^{-} ⟶ (1)$
${P b}^{2 +} (a q) + 2 e^{-} ⟶ {P b}^{0} (s) ⟶ (2)$
Now Multiplying equation $(1)$ by $2$ and multiplying equation $(2)$ by $3$ followed by adding will give :
${2 C r}^{0} (s) ⟶ 2 {C r}^{3 +}$
$3 {P b}^{2 +} ⟶ 3 {P b}^{0} (s) - ------------------- -$
$2 C r (s) + 3 {P b}^{2 +} = 2 {C r}^{3 +} + 3 P b$
or, $2 C r (s) + 3 P b {({N O}_{3})}_{2} (a q) = 2 C r {({N O}_{3})}_{2} (a q) + 3 P b (s)$

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