Balance the following equation- IO-4 - I- - H- - I2 - H2O

The correct option is B IO^ _4 +7 I^ +8 H^+ → 4I_2 + 4H_2O The unbalanced redox equation is as follows: IO^ _4 + I^ + H^+ → I_2 + H_2O All atoms oth ...

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Standard XII

Chemistry

Units and Dimensions

Balance the f...

Question

Balance the following equation.

${I O}_{4}^{-} + I^{-} + H^{+} \to I_{2} + H_{2} O$

{2 I O}_{4}^{-} + 14 I^{-} + 16 H^{+} \to 8 I_{2} + 8 H_{2} O

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{2 I O}_{4}^{-} + 14 I^{-} + 4 H^{+} \to 3 I_{2} + 8 H_{2} O

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{I O}_{4}^{-} + 7 I^{-} + 8 H^{+} \to 4 I_{2} + 4 H_{2} O

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Solution

The correct option is B ${I O}_{4}^{-} + 7 I^{-} + 8 H^{+} \to 4 I_{2} + 4 H_{2} O$
The unbalanced redox equation is as follows:
${I O}_{4}^{-} + I^{-} + H^{+} \to I_{2} + H_{2} O$
All atoms other than H and O are balanced.
The oxidation number of iodine changes from -1 to 0. The change in the oxidation number of iodine is 1.
The oxidation number of iodine changes from +7 to 0. The change in the oxidation number of iodine is 7.
The increase in the oxidation number is balanced with decrease in the oxidation number by multiplying
$I^{-}$ and $I_{2}$ with 7.
${I O}_{4}^{-} + 7 I^{-} + H^{+} \to 4 I_{2} + H_{2} O$
O atoms are balanced by adding 3 water molecules on RHS.
${I O}_{4}^{-} + 7 I^{-} + H^{+} \to 4 I_{2} + 4 H_{2} O$
Hydrogen atoms are balanced by adding 7 $H^{+}$ atoms on the RHS.
${I O}_{4}^{-} + 7 I^{-} + 8 H^{+} \to 4 I_{2} + 4 H_{2} O$
This is the balanced chemical equation.

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Similar questions

Balance the following below equation.

I_{2} + C r_{2} O_{7}^{2 -} + H^{+} \to C r^{3 +} + {I O}_{3}^{-} + H_{2} O

Q. Fill the missing products in the following reactions.

(i) 2 M n O_{4}^{-} + 16 H^{+} + 10 I^{-} \to 2 M n^{2 +} + 8 H_{2} O +

_______

(i i) 2 M n O_{4}^{-} + H_{2} O + I^{-} \to 2 M n O_{2} + 2 O H^{-} +

_______

The complete balanced equation is:

C l_{2} + {I O}_{3}^{-} + O H^{-} \to {I O}_{4}^{-} + C l^{-} + H_{2} O

Q. Balance the following equation by ion electron method:

C r I_{3} + H_{2} O_{2} + O H^{-} \to C r O_{4}^{2 -} + I O_{4}^{-} + H_{2} O

Q. Consider the reaction,

H^{+} + I O_{4}^{-} + I^{-} \to I_{2} + H_{2} O

. The ratio of the coefficients of

I O {_{4}}^{-}, I^{-}

and

I_{2}

, respectively, are:

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Balance the following equation.IO−4+I−+H+→I2+H2O

Balance the following equation.

${I O}_{4}^{-} + I^{-} + H^{+} \to I_{2} + H_{2} O$