Balance the following equation.
$P b S + O_{2} ⟶ P b O + S O_{2}$

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Solution

$P b S + O_{2} \to P b O + S O_{2}$
It is a double displacement reaction. Balanced equation is,
Keep oxygen in elementary state & balance other atoms,
$P b S + 3 O \to P b O + S O_{2}$
Now, Multiply by $2$
$2 P b S + 3 O_{2} \to 2 P b O + 2 S O_{2}$

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P b S

P b S A i r ⟶ Δ P b O + {S O}_{2}

P b S A i r ⟶ Δ P b O + {S O}

F e S_{2} + O_{2} \to F e_{2} O_{3} + S O_{2}

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(a) $F e S O_{4}$ $H e a t ⟶$ $F e_{2} O_{3} + S O_{2} + S O_{3}$

(b) $P b (N O_{3})_{2} (s)$ $H e a t ⟶$ $P b O (s) + N O_{2} (g) + O_{2} (g)$

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