Balance the following equation stepwise.
a. H2S2O7(l) + H2O(l) → H2SO4(l)
b. SO2(g) + H2S(aq) → S(s) + H2O(l)
c. Ag(s) + HCl(aq) → AgCl ↓+ H2 ↑
d. NaOH(aq) + H2SO4(aq) → Na2SO4(aq) + H2O(l)
a. H2S2O7(l) + H2O(l) → H2SO4(l)
b. SO2(g) + H2S(aq) → S(s) + H2O(l)
c. Ag(s) + HCl(aq) → AgCl ↓+ H2 ↑
d. NaOH(aq) + H2SO4(aq) → Na2SO4(aq) + H2O(l)
a. H2S2O7(l) + H2O(l) → H2SO4(l)
Step1. Count the number of each atom in reactant side:
H= 4
S=2
O=8
Step2. Count the number of each atom in product side:
H= 2
S=1
O=4
Step3.Then balance the number of each atom in an equation by multiplying reactant and product side with numeral value:
If we multiply product side by 2, then number of atoms in product and reactant side gets balance.
H2S2O7(l) + H2O(l) → 2H2SO4(l)
b. SO2(g) + H2S(aq) → S(s) + H2O(l)
Step1. Count the number of each atom in reactant side:
H= 2
S=2
O=2
Step2. Count the number of each atom in product side:
H= 2
S=1
O=2
Step3.Then balance the number of each atom in an equation by multiplying reactant and product side with numeral value:
If we multiply H2S by 2 in the reactant side and S by 3 and H2O by 2 in the product side, then number of atoms in product and reactant side gets balance.
SO2(g) + 2H2S(aq) → 3S(s) + 2H2O(l)
c. Ag(s) + HCl(aq) → AgCl ↓+ H2 ↑
Step1. Count the number of each atom in reactant side:
H= 1
Ag=1
Cl=1
Step2. Count the number of each atom in product side:
H= 2
Ag=1
Cl=1
Step3.Then balance the number of each atom in an equation by multiplying reactant and product side with numeral value:
If we multiply Ag by 2 and HCl by 2 in the reactant side and AgCl by 2 in the product side, then number of atoms in product and reactant side gets balance.
2Ag(s) + 2HCl(aq) → 2AgCl ↓+ H2 ↑
d. NaOH(aq) + H2SO4(aq) → Na2SO4(aq) + H2O(l)
Step1. Count the number of each atom in reactant side:
Na= 1
H=3
O=5
S=1
Step2. Count the number of each atom in product side:
Na= 2
H=2
O=5
S=1
Step3.Then balance the number of each atom in an equation by multiplying reactant and product side with numeral value:
If we multiply NaOH by 2 in the reactant side and H2O by 2 in the product side, then number of atoms in product and reactant side gets balance.
2NaOH(aq) + H2SO4(aq) → Na2SO4(aq) +2H2O(l)
a. H2S2O7(l) + H2O(l) → H2SO4(l)
Step1. Count the number of each atom in reactant side:
H= 4
S=2
O=8
Step2. Count the number of each atom in product side:
H= 2
S=1
O=4
Step3.Then balance the number of each atom in an equation by multiplying reactant and product side with numeral value:
If we multiply product side by 2, then number of atoms in product and reactant side gets balance.
H2S2O7(l) + H2O(l) → 2H2SO4(l)
b. SO2(g) + H2S(aq) → S(s) + H2O(l)
Step1. Count the number of each atom in reactant side:
H= 2
S=2
O=2
Step2. Count the number of each atom in product side:
H= 2
S=1
O=2
Step3.Then balance the number of each atom in an equation by multiplying reactant and product side with numeral value:
If we multiply H2S by 2 in the reactant side and S by 3 and H2O by 2 in the product side, then number of atoms in product and reactant side gets balance.
SO2(g) + 2H2S(aq) → 3S(s) + 2H2O(l)
c. Ag(s) + HCl(aq) → AgCl ↓+ H2 ↑
Step1. Count the number of each atom in reactant side:
H= 1
Ag=1
Cl=1
Step2. Count the number of each atom in product side:
H= 2
Ag=1
Cl=1
Step3.Then balance the number of each atom in an equation by multiplying reactant and product side with numeral value:
If we multiply Ag by 2 and HCl by 2 in the reactant side and AgCl by 2 in the product side, then number of atoms in product and reactant side gets balance.
2Ag(s) + 2HCl(aq) → 2AgCl ↓+ H2 ↑
d. NaOH(aq) + H2SO4(aq) → Na2SO4(aq) + H2O(l)
Step1. Count the number of each atom in reactant side:
Na= 1
H=3
O=5
S=1
Step2. Count the number of each atom in product side:
Na= 2
H=2
O=5
S=1
Step3.Then balance the number of each atom in an equation by multiplying reactant and product side with numeral value:
If we multiply NaOH by 2 in the reactant side and H2O by 2 in the product side, then number of atoms in product and reactant side gets balance.
2NaOH(aq) + H2SO4(aq) → Na2SO4(aq) +2H2O(l)
