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Question

Balance the following equations:

AsO33+MnO4AsO34+MnO2+H2O (Acid medium)

A
3AsO33+2MnO4+2H3AsO34+2MnO2+H2O
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B
3AsO33+2MnO4+4H3AsO34+3MnO2+H2O
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C
3AsO33+MnO4+H3AsO34+3MnO2+H2O
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D
None of these
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Solution

The correct option is A 3AsO33+2MnO4+2H3AsO34+2MnO2+H2O
The unbalanced redox equation is as follows:
AsO33+MnO4AsO34+MnO2+H2O
All atoms other than H and O are balanced.
The oxidation number of As changes from +3 to +5. The change in the oxidation number of As is +2.
The oxidation number of Mn changes from +7 to +4. The change in the oxidation number of Mn is 3.
The increase in the oxidation number is balanced with decrease in the oxidation number by multiplying
AsO33 and AsO34 with 3 and multiplying MnO4 and MnO2 with 2.
3AsO33+2MnO43AsO34+2MnO2+H2O
O atoms are balanced.
3AsO33+2MnO43AsO34+2MnO2+H2O
Hydrogen atoms are balanced by adding 2 H+ atoms on the LHS.
3AsO33+2MnO4+2H+3AsO34+2MnO2+H2O
This is the balanced chemical equation.

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