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Question

Balance the following equations by ion electron method:
I2+OHIO3+I+H2O.

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Solution

I2+OHIO3+I+H2O
1st step: Splitting into two half reactions,
I2+OHIO3+H2O(Oxidationhalfreaction); I2I(Reductionhalfreaction)
2nd step: Adding OH ions,
I2+12OH2IO3+6H2O
3rd step: Adding electrons to the sides deficient in electrons,
I2+12OH2IO3+6H2O+10e;I2+2e2I
4th step: Balancing electrons in both the half reactions,
I2+12OH2IO3+6H2O+10e
5[I2+2e2I]
5th step: Adding both the half reactions,
6I2+12OH2IO3+10I+6H2O
Dividing by 2,
3I2+6OHIO3+5I+3H2O.

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