I2+OH−→IO−3+I−+H2O
1st step: Splitting into two half reactions,
I2+OH−→IO−3+H2O(Oxidationhalfreaction); I2→I−(Reductionhalfreaction)
2nd step: Adding OH− ions,
I2+12OH−→2IO−3+6H2O
3rd step: Adding electrons to the sides deficient in electrons,
I2+12OH−→2IO−3+6H2O+10e;I2+2e→2I−
4th step: Balancing electrons in both the half reactions,
I2+12OH−→2IO−3+6H2O+10e
5[I2+2e−→2I−]
5th step: Adding both the half reactions,
6I2+12OH−→2IO−3+10I−+6H2O
Dividing by 2,
3I2+6OH−→IO−3+5I−+3H2O.