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Question

Balance the following equations by ion electron method.
KI+Cl2KCl+I2.

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Solution

KI+Cl2KCl+I2
Ionic equation, I+Cl2Cl+I2
1st step: Splitting into two half reactions,
II2(Oxidation); Cl2Cl(Reduction)
2nd step: Making number of atoms equal,
2II2; Cl22Cl
3rd step: Adding electrons to the sides deficient in electrons,
2II2+2e;Cl2+2e2Cl
4th step: Adding both the half reactions,
2I+Cl2I2+2Cl
Converting it into molecular form,
2K++2I+Cl2I2+2Cl+2K+
or
2KI+Cl2I2+2KCl.

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