Balance the following equations by the oxidation number method. (i) Fe2+ + H+ + Cr2O7 2– → Cr3+ + Fe3+ + H2O (ii) MnO2 + C2O4 2– → Mn2+ + CO2

Open in App

Solution

Suggest Corrections

Similar questions

C r_{2} O_{7}^{2 -} + H^{+} + I^{-} \to C r^{3 +} + I_{2} + H_{2} O

C r_{2} O_{7}^{2 -} + F e_{2}^{+} + H^{+} \to C r^{3 +} + F e^{3 +} + H_{2} O

M n O^{4 -} + S O_{3}^{2 -} + H^{+} \to M n^{2 +} + S O_{4}^{2 -} + H_{2} O

M n O^{4 -} + H^{+} + B r^{-} \to M n^{2 +} + B r_{2} + H_{2} O

{M n O_{4}}^{-} + F e^{2 +} + H^{+} \to M n^{2 +} + F e^{3 +} + H_{2} O

{C r_{2} O_{7}}^{2 -} + H N O_{2} + H^{+} \to C r^{3 +} + {N O_{3}}^{-} + H_{2} O

The oxidation half reaction for following reaction is

Fe²⁺(aq) + Cr₂O₇^2-(aq) → Fe³⁺ (aq) + Cr³⁺(aq)

{M n O_{4}}^{2 -} + H^{+} \to M n O_{2} + {M n O_{4}}^{-} + H_{2} O

Join BYJU'S Learning Program