Balance the following in basic medium- Zn - NO-3 - ZnO2-2 - NH3

The correct option is B 4Zn + NO^ _3 + 7OH^ → 4ZnO^2 _2 + 2H_2O+NH_3 The unbalanced redox equation is as follows: Zn + NO^ _3 → ZnO^2 _2 + NH_3 All a ...

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Byju's Answer

Standard XII

Chemistry

Oxidation Number Method

Balance the f...

Question

Balance the following in basic medium:

$Z n + {N O}_{3}^{-} \to Z n O_{2}^{2 -} + N H_{3}$

4 Z n + {N O}_{3}^{-} + 7 O H^{-} \to 4 Z n O_{2}^{2 -} + 2 H_{2} O + N H_{3}

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4 Z n + {N O}_{3}^{-} + 7 O H^{-} \to 2 Z n O_{2}^{2 -} + 2 H_{2} O + 2 N H_{3}

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4 Z n + {N O}_{3}^{-} + 14 O H^{-} \to 4 Z n O_{2}^{2 -} + 2 H_{2} O + N H_{3}

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Solution

The correct option is B $4 Z n + {N O}_{3}^{-} + 7 O H^{-} \to 4 Z n O_{2}^{2 -} + 2 H_{2} O + N H_{3}$
The unbalanced redox equation is as follows:
$Z n + {N O}_{3}^{-} \to Z n O_{2}^{2 -} + N H_{3}$
All atoms other than H and O are balanced.
The oxidation number of Zn changes from 0 to +2. The change in the oxidation number of Zn is +2.
The oxidation number of N changes from +5 to -3. The change in the oxidation number of N is 8.
The increase in the oxidation number is balanced with decrease in the oxidation number by multiplying
$Z n$ and $Z n O_{2}^{2 -}$ with 4.
$4 Z n + {N O}_{3}^{-} \to 4 Z n O_{2}^{2 -} + N H_{3}$
O atoms are balanced by adding 5 water molecules on LHS..
$4 Z n + {N O}_{3}^{-} + 5 H_{2} O \to 4 Z n O_{2}^{2 -} + N H_{3}$
Hydrogen atoms are balanced by adding 7 $H^{+}$ atoms on the LHS.
$4 Z n + {N O}_{3}^{-} + 5 H_{2} O \to 4 Z n O_{2}^{2 -} + N H_{3} + 7 H^{+}$
Since the reaction occurs in basic medium, add 7 hydroxide ions on both sides of the equation.
$4 Z n + {N O}_{3}^{-} + 5 H_{2} O + 7 O H^{-} \to 4 Z n O_{2}^{2 -} + N H_{3} + 7 H^{+} + 7 O H^{-}$
On RHS, 7 $H^{+}$ ions combine with 7 $O H^{-}$ ions to form 2 water molecules out of which, five water molecules cancels with one water molecule on LHS.
$4 Z n + {N O}_{3}^{-} + 7 O H^{-} \to 4 Z n O_{2}^{2 -} + N H_{3} + 2 H_{2} O$
This is the balanced chemical equation.

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Similar questions

Q. Balance the following equation by ion electron method.

Z n + N O_{3}^{-} + O H^{-} \to Z n O_{2}^{2 -} + N H_{3} + H_{2} O

(alkaline medium)

Q. The balanced equation for the following:

4 Z n + 10 H {N O}_{3} \to 4 Z n {({N O}_{3})}_{2} + N_{2} O + 5 H_{2} O

If the statement is true enter 1 else 0.

Balance the following redox reaction in basic medium:

M n O_{4}^{-} + {N O}_{2}^{-} ⟶ M n O_{2} + {N O}_{3}^{-}

Balance the following redox reactions in acidic medium :

Z n + {N O}_{3}^{-} ⟶ {Z n}^{2 +} + N_{2}

The secondary reactions which takes place in dry cell are:

1) $M n O_{2} + N H_{4}^{+} + e^{-} \to M n O (O H) + N H_{3}$

2) $2 N H_{4} C l + 2 (O H^{-}) \to$ $2 N H_{3} + 2 C l^{-} + 2 H_{2} O$

3) $Z n + 2 M n O_{2} \to$ $[Z n (N H_{3})_{2}] + 2 O H^{-} + 2 M n O (O H)$

4) $Z n^{2 +} 2 N H_{3} + 2 C l^{-} \to$ $[Z n (N H_{3})_{2}] C l_{2} or Z n C l_{2} .2 N H_{3}$

Correct statements are:

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Balance the following in basic medium:Zn+NO−3→ZnO2−2+NH3

Balance the following in basic medium:

$Z n + {N O}_{3}^{-} \to Z n O_{2}^{2 -} + N H_{3}$