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Question

Balance the following reaction.
MnO4+H2O2MnO2+O2

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Solution

To balance MnO4+H2O2MnO2+O2
(1) Oxidation H21O20O2+2e
Reduction +7MnO4+3e+4MnO2

(2) Balancing the atoms & charge
H2O2+2OHO2+2e
MnO4+3eMnO2+4OH
Balance O-atoms,
H2O2+2OHO2+2e+2H2O(1)
MnO4+3e+2H2OMnO2+4OH(2)

(3) Electron gain equivalent to electron lost
(1)×3 & (2)×2
3H2O2+6OH3O2+6e+6H2O(3)
2MnO4+6e+4H2O2MnO2+8OH(4)
Adding & simplifying (3) & (4) we get,
3H2O2+2MnO42MnO2+3O2+2OH+2H2O

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