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Question

Balance the following reaction.
SbCl3+KIO3+HCISbCl5+ICl+H2O+KCl

A
2SbCl3+KlO3+6HCl2SbCl5+ICl+3H2O+KCl
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B
SbCl3+KIO3+4HCl2SbCl5+ICl+3H2O+KCl
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C
2SbCl3+KIO3+4HCI2SbCl5+5ICl+2H2O+KCl
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D
None of these
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Solution

The correct option is D 2SbCl3+KlO3+6HCl2SbCl5+ICl+3H2O+KCl
The unbalanced redox equation is as follows:
SbCl3+KIO3+HClSbCl5+ICl+H2O+KCl
Balance all atoms other than H and O.
SbCl3+KIO3+4HClSbCl5+ICl+H2O+KCl
The oxidation number of Sb changes from 3 to 5. The change in the oxidation number of Sb is 2.
The oxidation number of I changes from 5 to 1. The change in the oxidation number of I is 4.
The increase in the oxidation number is balanced with decrease in the oxidation number by multiplying
SbCl3 and SbCl5 with 2. Also balance Cl atoms.
2SbCl3+KIO3+6HCl2SbCl5+ICl+H2O+KCl
O atoms are balanced by adding 2 water molecules on RHS.
2SbCl3+KIO3+6HCl2SbCl5+ICl+2H2O+KCl
Hydrogen atoms are balanced.
2SbCl3+KIO3+6HCl2SbCl5+ICl+3H2O+KCl
This is the balanced chemical equation.

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