Balance the following redox reaction:

$M n O_{4}^{-} + H^{+} + H_{2} O_{2} ⟶ {M n}^{2 +} + O_{2}$

2 M n O_{4}^{-} + 6 H^{+} + 5 H_{2} O_{2} ⟶ 2 {M n}^{2 +} + 5 O_{2} + 8 H_{2} O

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2 M n O_{4}^{-} + 6 H^{+} + 3 H_{2} O_{2} ⟶ 2 {M n}^{2 +} + 6 O_{2} + 8 H_{2} O

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4 M n O_{4}^{-} + 6 H^{+} + 5 H_{2} O_{2} ⟶ 2 {M n}^{2 +} + 5 O_{2} + 8 H_{2} O

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None of these

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Solution

The correct option is A $2 M n O_{4}^{-} + 6 H^{+} + 5 H_{2} O_{2} ⟶ 2 {M n}^{2 +} + 5 O_{2} + 8 H_{2} O$
The unbalanced redox equation is as follows:

$M n O_{4}^{-} + H^{+} + H_{2} O_{2} ⟶ {M n}^{2 +} + O_{2}$

All atoms other than H and O are balanced.
The oxidation number of Mn changes from 7 to 2. The change in the oxidation number of Mn is 5.

The oxidation number of O changes from -1 to -2. The change in the oxidation number per O atom is 1. Total change in the oxidation number for 2 O atoms is 2.

The increase in the oxidation number is balanced with a decrease in the oxidation number by multiplying $M n O_{4}^{-}$ and $M n^{2 +}$ with 2 and by multiplying $H_{2} O_{2}$ and $O_{2}$ with 5.

$2 M n O_{4}^{-} + H^{+} + 5 H_{2} O_{2} ⟶ 2 {M n}^{2 +} + 5 O_{2}$

O atoms are balanced by adding 8 water molecules on RHS.
$2 M n O_{4}^{-} + H^{+} + 5 H_{2} O_{2} ⟶ 2 {M n}^{2 +} + 5 O_{2} + 8 H_{2} O$

To balance H atoms, add 6 $H^{+}$ on RHS.
$2 M n O_{4}^{-} + 5 H_{2} O_{2} + 6 H^{+} ⟶ 2 {M n}^{2 +} + 5 O_{2} + 8 H_{2} O$

This is the balanced chemical equation.

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Similar questions

O^{18}

2 M n O_{4}^{-} + 5 H_{2} O_{2}^{18} + 6 H^{+} \to 2 M n^{2 +} + 8 H_{2} O + 5 O_{2}

2 M n O_{4}^{-} + 5 H_{2} C_{2} O_{4} + 6 H^{+} \to 2 M n^{2 +} + 10 C O_{2} + 8 H_{2} O

{2 m n O}_{4}^{-} + 6 H^{+} + {5 H}_{2} C_{2} O_{4} ⇌ {2 M N}^{2 +} + 8 H_{2} O + {10 C O}_{2}

E_{{M n O}_{4} M n^{2 +},}^{0} = 1.51 V

E_{{C O}_{3} C_{2} O_{4}^{2 -}}^{0} = - 0.49 V

20

H_{2} O_{2}

46.9

0.145

K M n O_{4}

2 M n O_{4}^{-} + 5 H_{2} O_{2} + 6 H^{+} ⟶ 2 M n^{2 +} + 5 O_{2} + 8 H_{2} O

%

H_{2} O_{2}

2 {K M n O}_{4} + 5 H_{2} S + {6 H}^{+} \to {2 M n}^{2 +} + {2 K}^{+} + 5 S + {8 H}_{2} O

1

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