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Question

Balance the given equation.
Al+Cl2AlCl3.

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Solution

The given reaction is as follow:
Al+Cl2AlCl3
There are 3 chlorine on product side and only 2 chlorine on reactant side. Thus multiply chloriine on reactant side by 3 and chlorine on product side by 2 to make them equal.
Al+3Cl22AlCl3
Now, there are two Al atom on product side but only one Al atom on reactant side. Thus, muliply Al by 2 on reactant side.
2Al+3Cl22AlCl3
Balanced reaction: 2Al+3Cl22AlCl3

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