Balance the given equation by ion electron method: Na_{2 }O_4+BrO_3^-+H_2O=NO_3^-+Br^-+H^+

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C u_{2} O + H^{+} + N O_{3}^{-} \to C u^{2 +} + N O + H_{2} O

A s_{2} S_{3} + N O_{3}^{-} + H^{+} + H_{2} O \to H_{3} A s O_{4} + N O + S

C u + N O_{3}^{-} + 8 H^{+} \to C u (N O_{3})_{2} + N O + H_{2} O

Z n + B r O_{4}^{-} + O H^{-} + H_{2} O \to [Z n (O H)_{4}]^{2 -} + B r^{-}

{C r_{2} O_{7}}^{2 -} + H^{+} + {C_{2} O_{4}}^{2 -} \to C r^{3 +} + C O_{2} + H_{2} O

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