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Question

Balance the given equation.
KClO3KCl+O2.

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Solution

KClO3KCl+3O2
There are 6 O on the right and 3 on the left
so multiply the KClO3 by 2
2KClO3KCl+3O2
now there are 6 O on both sides
Balance the K and Cl by multiplying KCl on the right by 2
2KClO32KCl+3O2

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