Question

# Balance the given equation.$$KClO_3\rightarrow KCl+O_2$$.

Solution

## $$KClO_3 \rightarrow KCl + 3O_2$$ There are 6 O on the right and 3 on the left so multiply the $$KClO_3$$ by 2 $$2KClO_3 \rightarrow KCl + 3O_2$$ now there are 6 O on both sides Balance the K and Cl by multiplying KCl on the right by 2 $$2 KClO_3 \rightarrow 2KCl + 3O_2$$Chemistry

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