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Question

Balance the given equation.
$$KClO_3\rightarrow KCl+O_2$$.


Solution

$$KClO_3 \rightarrow KCl + 3O_2$$ 
There are 6 O on the right and 3 on the left 
so multiply the $$KClO_3$$ by 2 
$$2KClO_3 \rightarrow KCl + 3O_2$$ 
now there are 6 O on both sides 
Balance the K and Cl by multiplying KCl on the right by 2 
$$2 KClO_3 \rightarrow 2KCl + 3O_2$$

Chemistry

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