Question

Balance the reactions:
${CH}_4+O_2\to {CO}_2+H_{2}O$

Answer 1

The given reaction is a combustion reaction of methane.

The given reaction is

$C{H}_4+O_2\to C{O}_2+H_{2}O$

First, we will balance carbon and hydrogen.

There are four hydrogens on the left side of the reaction and two hydrogens on the right-hand side.

Thus we will multiply right-hand side hydrogen molecule with 2.

$C{H}_4+O_2\to C{O}_2+2H_{2}O$

Now, we will balance oxygen.

There is four oxygen on the right-hand side and only two on the lefthand side. Thus we will multiply left-hand side oxygen by 2.

Thus, the balance chemical reaction will be:

$C{H}_4+2O_2\to C{O}_2+2H_{2}O$