Balanced equation for the reaction between zinc and dilute sulphuric acid is :

Z n + H_{2} {S O}_{4} (d i l) \to {Z n S O}_{4} + 2 H_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Z n + 2 H_{2} {S O}_{4} (d i l) \to {Z n S O}_{4} + 2 H_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 Z n + H_{2} {S O}_{4} (d i l) \to 2 {Z n S O}_{4} + H_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Z n + H_{2} {S O}_{4} (d i l) \to {Z n S O}_{4} + H_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $Z n + H_{2} {S O}_{4} (d i l) \to {Z n S O}_{4} + H_{2}$
$Z n + H_{2} {S O}_{4} (d i l) \to {Z n S O}_{4} + H_{2}$

Suggest Corrections

Similar questions

2 C_{12} H_{22} O_{11} + H_{2} {S O}_{4} (c o n c) \to 12 C + 5 H_{2} O + H_{2} {S O}_{4} (d i l)

P b {(N O_{x})}_{2} + H_{2} {S O}_{4} (d i l) \to {P b S O}_{4} ↓ + {y H N O}_{3}

Z n + H_{2} {S O}_{4} \to Z n {S O}_{4} + H_{2}

1.5 \times 10^{- 2} m o l

Z n {S O}_{4}

2.0 \times 10^{- 2} m o l

Z n

Z n + H_{2} S O_{4} (d i l) \to Z n S O_{4} + H_{2} ↑

1.	Column-A Types of chemical reaction		Column-B Chemical equation
(A)	Combination reaction	(i)	$Z n + H_{2} S O_{4} \to Z n S O_{4} + H_{2}$
(B)	Oxidation & reduction reaction	(ii)	$2 H_{2} O E l e c t r i c i t y ⟶ 2 H_{2} + O_{2}$
(C)	Decomposition reaction	(iii)	$C a O + C O_{2} \to C a C O_{3}$
(D)	Displacement reaction	(iv)	$H_{2} + C l_{2} \to 2 H C l$
(E)	Double Displacement reaction	(v)	$B a C l_{2} + N a_{2} S O_{4} \to B a S O_{4} ↓ + N a C l$

Join BYJU'S Learning Program