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S Block Elements

Balanced equa...

Question

Balanced equation for the reaction of conc. sulphuric acid with cellulose is :

C_{6} H_{10} O_{5} + H_{2} {S O}_{4} (c o n c) \to 6 C + 5 H_{2} O + H_{2} {S O}_{4} (d i l)

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C_{6} H_{10} O_{5} + H_{2} {S O}_{4} (c o n c) \to 6 C + 5 H_{2} O + H_{2} {S O}_{4} (c o n c)

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C_{6} H_{10} O_{5} + H_{2} {S O}_{4} (d i l) \to 6 C + 5 H_{2} O + H_{2} {S O}_{4} (d i l)

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C_{6} H_{10} O_{5} + H_{2} {S O}_{4} (d i l) \to 6 C + 5 H_{2} O + H_{2} {S O}_{4} (c o n c)

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Solution

The correct option is A $C_{6} H_{10} O_{5} + H_{2} {S O}_{4} (c o n c) \to 6 C + 5 H_{2} O + H_{2} {S O}_{4} (d i l)$
$C_{6} H_{10} O_{5} + H_{2} {S O}_{4} (c o n c) \to 6 C + 5 H_{2} O + H_{2} {S O}_{4} (d i l)$

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Similar questions

2 C_{12} H_{22} O_{11} + H_{2} {S O}_{4} (c o n c) \to 12 C + 5 H_{2} O + H_{2} {S O}_{4} (d i l)

P b {(N O_{x})}_{2} + H_{2} {S O}_{4} (d i l) \to {P b S O}_{4} ↓ + {y H N O}_{3}

25^{o} C

H_{2}

(C_{6} H_{12})

(C_{6} H_{10})

- 241, - 3920

- 3800

k J / m o l

a_{1}, a_{2}, \dots, a_{10}

h_{1}, h_{2}, \dots, h_{10}

a_{1} = h_{1} = 2

a_{10} = h_{10} = 3

a_{4} h_{7}

H_{2} {S O}_{4}

P_{2} O_{5}

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