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Byju's Answer
Standard XII
Chemistry
Preparation of Dioxygen
Balanced equa...
Question
Balanced equation for the reaction of ethane & oxygen in presence of molybdenum oxide.
A
C
2
H
6
+
O
2
M
o
O
/
[
350
−
500
o
C
]
−
−−−−−−−−−−
→
C
H
3
C
H
O
+
H
2
O
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B
C
2
H
4
+
O
2
M
o
O
/
[
350
−
500
o
C
]
−
−−−−−−−−−−
→
C
H
3
C
H
O
+
H
2
O
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C
C
2
H
6
+
1.5
O
2
M
o
O
/
[
350
−
500
o
C
]
−
−−−−−−−−−−
→
C
H
3
C
O
O
H
+
H
2
O
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D
C
2
H
4
+
O
2
M
o
O
/
[
350
−
500
o
C
]
−
−−−−−−−−−−
→
C
H
3
C
O
O
H
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Solution
The correct option is
A
C
2
H
6
+
O
2
M
o
O
/
[
350
−
500
o
C
]
−
−−−−−−−−−−
→
C
H
3
C
H
O
+
H
2
O
Reaction:
C
2
H
6
+
O
2
M
o
O
/
[
350
−
500
o
C
]
−
−−−−−−−−−−
→
C
H
3
C
H
O
+
H
2
O
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0
Similar questions
Q.
A mixture of ethane
(
C
2
H
6
)
and ethene
(
C
2
H
4
)
occupies
40
L
at
1.00
atm and
400
K
. The mixture reacts completely with
130
g
of
O
2
to produce
C
O
2
and
H
2
O
. Assuming ideal gas behaviour, mole fractions of
C
2
H
4
and
C
2
H
6
in the mixture will be :
Q.
A mixture of ethane
(
C
2
H
6
)
and ethene
(
C
2
H
4
)
occupies 40 L at 1.00 atm and at 400 K.The mixture reacts completely with 130 g of
O
2
to produce
C
O
2
and
H
2
O
. Assuming ideal gas behaviour, calculate the mole fractions of
C
2
H
4
and
C
2
H
6
in the mixture.
Q.
An ideal gaseous mixture of ethane (
C
2
H
6
) and ethene (
C
2
H
4
) occupies 28 litre at 1 atm and 273 K. The mixture reacts completely with 128 gm
O
2
to produce
C
O
2
and
H
2
O
. Mole fraction at
C
2
H
4
in the mixture is:
Q.
An ideal gas mixture of ethane
(
C
2
H
6
)
and ethene
(
C
2
H
4
)
occupies 28 litres at 1 atm and 273 K. The mixture reacts completely with 128 g of
O
2
to produce
C
O
2
and
H
2
O
. The mole fraction of
C
2
H
6
in the mixture is:
Q.
An ideal gas mixture of ethane
(
C
2
H
6
)
and ethene
(
C
2
H
4
)
occupies 28 litres at 1 atm and 273 K. The mixture reacts completely with 128 g of
O
2
to produce
C
O
2
and
H
2
O
. The mole fraction of
C
2
H
6
in the mixture is:
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