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Question

Ball 1 collides head on with another identical ball 2, initially at rest. Velocity of ball 2 after collision becomes two times that of ball 1 after collision. The coefficient of restitution between the two balls is :

A
e=13
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B
e=12
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C
e=14
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D
e=23
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Solution

The correct option is A e=13Before collision, After collision, Now, e=rel. velocity of separationrel. velocity of approach ⇒e=2V−VU=VU−(1) According to conservation of momentum principle, m(U)+m×0=mV+m(2V) ⇒3V=U⇒VU=13−(2) From (1) & (2), we get, e=13 Hence, (A) is the correct answer.

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