Question

balnce the equation by half equation mathod ? Zn+HC​​^​L---ZnCL₂+H₂

Answer 1

$$\begin{gathered} Oxidation \\ Zn\to Z{n}^{2+}+2e^{-}-----1 \\ Reduction \\ HCl+e^{-}\to H_2+C{l}^{-} \\ Balancetheaboveequation \\ 2HCl+2e^{-}\to H_2+2C{l}^{-}----2 \\ Nowaddequation1and2 \\ Zn\to Z{n}^{2+}+2e^{-} \\ 2HCl+2e^{-}\to H_2+2C{l}^{-} \\ ------------ \\ Zn+2HCl\to Z{n}^{2+}+2C{l}^{-}+H_2 \\ ----------------- \\ or \\ Zn+2HCl\to ZnC{l}_2+H_2 \end{gathered}$$
Thus the equation is a balanced equation.