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Question

Barium Chloride+Aluminium SulphateBarium Sulphate+Aluminium Chloride

Which of the following options correctly represents the balanced chemical equation for the above reaction?


A

3BaCl3(aq) + Al(SO4)(s) Ba2(SO4)3(s) + 2AlCl2

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B

2BaCl3(aq) + 3Al(SO4)(s) Ba2(SO4)3(s) + 3AlCl2

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C

3BaCl2(aq) + Al2(SO4)3(s) 2Ba(SO4)(s) + 3AlCl3

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D

3BaCl2 + Al2(SO4)3 3BaSO4 + 2AlCl3

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Solution

The correct option is D

3BaCl2 + Al2(SO4)3 3BaSO4 + 2AlCl3


Barium Chloride + Aluminium Sulphate→ Barium Sulphate +Aluminium Chloride.

The skeleton reaction is BaCl2 + Al2(SO4)3 BaSO4+AlCl3

Consider Aluminium Sulphate compound first because it has more number of atoms, 2 atoms of Al are present on reactant side and 1 atom on product side, to balance Al, take the coefficient of AlCl3 on product side as 2.

So the equation becomes,BaCl2 + Al2(SO4)3 BaSO4+2AlCl3

Now consider the set (SO4) instead of S and O separately because it is present in reactant and product side in the same form. There are 3 sets on reactant side and 1 set on product side, to balance this, take the coefficient of BaSO4 as 3.

BaCl2 + Al2(SO4)3 3BaSO4+AlCl3

Now consider Ba, there are 3 atoms on product side and 1 atom on reactant side, to balance it, take the coefficient of BaCl2 as 3. The Cl atoms are also balanced.

3BaCl2 + Al2(SO4)3 3BaSO4+2AlCl3

The balanced reaction is,

3BaCl2 + Al2(SO4)3 3BaSO4+2AlCl3

BaCl2 and AlCl3 are soluble in water so written as (aq). BaSO4and Al2(SO4)3 are insoluble in water so written as (s).


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