Barium ions, $C N^{-}$ and $C o^{2 +}$ form an ionic complex. If that complex is supposed to be $75 %$ ionised in water with vant Hoff factor 'i' equal to four, then the coordination number of $C o^{2 +}$ in the complex can be.

Six

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Five

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Four

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Six and Four both

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Solution

The correct option is A Six
Complex formed is $B q_{2} [C O (C N)_{6}]$ in which oxidation of $C O$ is $(2 +)$ and $C N$ of $C O$ is six.

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Q. Barium ions,

C N^{-}

and

C o^{2 +}

form an ionic complex. If this complex is 75% ionised in aqueous solution with Van't Hoff factor (i) equal to four and paramagnetic moment is found to be 1.73 BM (due to spin only) then the hybridisation state to Co (II) in the complex will be :

Barium ions, $C N^{-}$ and $C o^{+ 2}$ form an ionic complex. If this complex is 75% ionized in aqueous solution with Vant Hoff factor(i) equal to four and paramagnetic moment is found to be 1.73 BM(due to spin only) then hybridization state of Co(II) in the complex will be

C o^{2 +} (a q .) + S C N^{-} (a q) \to

Complex

(X)

N i^{2 +} (a q) +

dimethylglyoxime

N H_{4} O H - ---- \to

Complex

(Y)

The coordination number of cobalt and nickel in both the complexes (X) and (Y) is four. The IUPAC names of the complexes (X) and (Y) are respectively :

C o^{2 +} (a q .) + S C N^{-} (a q .) \to C o m p l e x (X)

N i^{2 +} (a q .) + d i m e t h y l g l y o x i m e N H_{4} O H - ---- \to C o m p l e x (Y)

The coordination number of cobalt and nickel in both the complexes (X) and (Y) is four. The geometry of complexes (X) and (Y) are respectively :

C o^{2 +} (a q .) + S C N^{-} (a q .) \to C o m p l e x (X)

N i^{2 +} (a q .) + d i m e t h y l g l y o x i m e N H_{4} O H - ---- \to C o m p l e x (Y)

The coordination number of cobalt and nickel in both the complexes (X) and (Y) is four. Select the correct statement for the complexes (X) and (Y).

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Barium ions, CN− and Co2+ form an ionic complex. If that complex is supposed to be 75% ionised in water with vant Hoff factor 'i' equal to four, then the coordination number of Co2+ in the complex can be.

The correct option is A SixComplex formed is Bq2[CO(CN)6] in which oxidation of CO is (2+) and CN of CO is six.

Barium ions, $C N^{-}$ and $C o^{2 +}$ form an ionic complex. If that complex is supposed to be $75 %$ ionised in water with vant Hoff factor 'i' equal to four, then the coordination number of $C o^{2 +}$ in the complex can be.

The correct option is A Six
Complex formed is $B q_{2} [C O (C N)_{6}]$ in which oxidation of $C O$ is $(2 +)$ and $C N$ of $C O$ is six.