wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Based on equations reducible to linear equations, Solve for x and y: 6x+5y=8xy and 8x+3y=7xy

A
x=2,y=2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
x=1,y=2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
x=3,y=8
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
x=5,y=7
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B x=1,y=2

The given equations are
6x+5y=8xy....eq(1)

8x+3y=7xy....eq(2)

Divide both equations by xy

6y+5x=8....eq(3)

8y+31x=7....eq(4)

Put 1x=u and 1y=v in eq(3)and(4)

6v+5u=8....eq(5)

8v+3u=7....eq(6)

Multiply eq (5) by 3 and eq(6) by 5 and subtract both

(18v+15u=24)(40v+15u=35)

22v=11v=12

Put v=12 in eq(5)

6(12)+5u=8u=1

Hence,1x=u=1x=1

1y=v=12y=2


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Cramer's Rule
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon