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Question

Based on solute-solvent interactions, arrange the following in order of increasing solubility in n-octane and explain. 
Cyclohexane, $$KCl,\ CH_{3}OH,\ CH_{3}CN$$


Solution

n-Octane is non polar and can dissolve non-polar solutes. It cannot dissolve polar (and ionic) solutes.

$$\text{Cyclohexane}$$ is non-polar. Hence, easily soluble in n-octane.

$$\text{Methanol}$$ and $$\text{acetonitrile}$$ are polar and have very low solubility in n-octane.

$$\text{KCl}$$ is ionic compound and hence, insoluble in n-octane.

The increasing order for solubility in n-octane is as follows:

$$\displaystyle KCl < CH_3OH < CH_3CN < \text{Cyclohexane}$$

Chemistry
NCERT
Standard XII

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