wiz-icon
MyQuestionIcon
MyQuestionIcon
5
You visited us 5 times! Enjoying our articles? Unlock Full Access!
Question

Based on the above question. Match column-A with the column-B.

Column-AColumn-B
a.mA=mBp.I
b.mA>mBq.II
c.mA<mBr.III
s.IV
t.V
u.VI

169843_697f7d02c136413fa1d7c646c4f64089.png

A
a -u, b-r, c-p
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
a-q, b-t, c-s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
a-q, b-s, c-t
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
a-u, b-t, c-s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B a-q, b-t, c-s
From the momentum conservation principle we can say that the momentum of both the particle after exploding will remain same.
mava=mbvb

Slope of the Displacement-time curve gives the Velocity of that motion.
1. masses are same so velocity will also remain same, but in opposite direction.
2. mb>ma higher the mass lesser the velocity after the equilibrium. Less velocity less the slope.
3. mb<ma higher the mass, lesser the velocity after the equilibrium. Less velocity less the slope.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Why Is the Center of Mass the Real Boss?
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon