Based on the above question. Match column-A with the column-B.
Column-A
Column-B
a.
mA=mB
p.
I
b.
mA>mB
q.
II
c.
mA<mB
r.
III
s.
IV
t.
V
u.
VI
A
a -u, b-r, c-p
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B
a-q, b-t, c-s
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C
a-q, b-s, c-t
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D
a-u, b-t, c-s
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Solution
The correct option is B a-q, b-t, c-s From the momentum conservation principle we can say that the momentum of both the particle after exploding will remain same.
mava=mbvb
Slope of the Displacement-time curve gives the Velocity of that motion.
1. masses are same so velocity will also remain same, but in opposite direction.
2. mb>ma higher the mass lesser the velocity after the equilibrium. Less velocity less the slope.
3. mb<ma higher the mass, lesser the velocity after the equilibrium. Less velocity less the slope.