Based on VSEPR theory, the number of 90 degrees $F - B r - F$ angles in $B r F_{5}$ is:

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Solution

$B r F_{5}$ has square bipyramidal geometry with one lone pair of electron. Thereby forms a square pyramidal structure. Due to lone pair-bond pair repulsion the bond angle of axial lone pair and equatorial $F$ gets distorted and results in less than $90^{\circ}$ bond angle.
Therefore none of the $F - B r - F$ bond angle is of $90^{\circ}$ .

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