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Bases

Basic natural...

Question

Basic natural of oxides of group $13$ increases in the order.

B_{2} O_{3} < A l_{2} O_{3} < G a_{2} O_{3} < I n_{2} O_{3} < T l_{2} O_{3}

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T l_{2} O_{3} < I n_{2} O_{3} < G a_{2} O_{3} < A l_{2} O_{3} < B_{2} O_{3}

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B_{2} O_{3} > A l_{2} O_{3} > G a_{2} O_{3} < I n_{2} O_{3} < T l_{2} O_{3}

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B_{2} O_{3} \approx A l_{2} O_{3} < G a_{2} O_{3} \approx I n_{2} O_{3} < T l_{2} O_{3}

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Solution

The correct option is A $B_{2} O_{3} < A l_{2} O_{3} < G a_{2} O_{3} < I n_{2} O_{3} < T l_{2} O_{3}$
The basic Charecter of elements depends upon the metallic charecter of the elements. As the metallic charecter increases the basicity increases and vice versa. Hence for any particular group the atomic radius of the elements goes high as we go low in the group. Higer radii means that it would be more and more difficult for the nucleus to dominate over the valency shell electrons. Therefore there tendency to release electrons will increase. Therefore the metallic characteristics will increase which will also increase the basicity of the oxides. Therefore a clear conclusion can be made that as we go low in a group,the basicity of the oxides will increase. Therefore the sequence will be
$B_{2} O_{3} < A l_{2} O_{3} < G a_{2} O_{3} < I n_{2} O_{3} < T l_{2} O_{3}$ . It is increasing order of the basicity of the oxides of the 13 group

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