$. . . . B C l_{3} (g) + . . . H_{2} (g) \to . . . . H C l (g) + . . . . . B (s)$
When the above equation for the reaction represented is balanced and all coefficients are reduced to lowest whole-number terms, what will be the coefficient for HCl?

1

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Solution

The correct option is D $6$
The unbalanced chemical equation is $B C l_{3} (g) + H_{2} (g) \to H C l (g) + B (s)$
B atoms are balanced.
Balance chlorine atoms
$B C l_{3} (g) + H_{2} (g) \to 3 H C l (g) + B (s)$
Balance H atoms
$B C l_{3} (g) + 3 / 2 H_{2} (g) \to 3 H C l (g) + B (s)$
Multiply above equation with 2 so as to give whole number coefficents.
$2 B C l_{3} (g) + 3 H_{2} (g) \to 6 H C l (g) + 2 B (s)$
This is the balanced chemical equation.
The coefficient for $H C l$ is $6$ .

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