BD and CD are two tangents drawn to a circle with centre O. If $∠ B D C = 44^{o}$ , find $∠ B A C$ .

68^{o}

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32^{o}

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44^{o}

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96^{o}

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Solution

The correct option is A $68^{o}$
Given, $∠ B D C = 44^{o}$
$∠ D B O = ∠ D C O = 90^{o} ∠ B O C = 180^{o} - ∠ B D C ∠ B O C = 180^{o} - 44^{o} ∠ B O C = 136^{o} ∠ B O C = 2 ∠ B A C (h a l f a n g l e) ∠ B A C = \frac{136^{o}}{2} = 68^{o}$

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BD and CD are two tangents drawn to a circle with centre O. If ∠BDC=44o, find ∠BAC.

The correct option is A 68oGiven, ∠BDC=44o∠DBO=∠DCO=90o∠BOC=180o−∠BDC∠BOC=180o−44o∠BOC=136o∠BOC=2∠BAC(halfangle)∠BAC=136o2=68o

BD and CD are two tangents drawn to a circle with centre O. If $∠ B D C = 44^{o}$ , find $∠ B A C$ .

The correct option is A $68^{o}$
Given, $∠ B D C = 44^{o}$
$∠ D B O = ∠ D C O = 90^{o} ∠ B O C = 180^{o} - ∠ B D C ∠ B O C = 180^{o} - 44^{o} ∠ B O C = 136^{o} ∠ B O C = 2 ∠ B A C (h a l f a n g l e) ∠ B A C = \frac{136^{o}}{2} = 68^{o}$