Question

BD is a median of a triangle ABC. F is a point on AB such that CF intersects BD at E and $BE=BD$. If $BF=5$ cm. BA is equal to

• A. 10
• B. 12
• C. 15
• D. 17

Answer 1

The correct option is C 15

In a triangle $ABC$, $BD$ is a median of a triangle.
And $F$ is a point on $AB$ such that $CF$ intersects $BD$ at $E$.
Also given $BE=ED,BF=5cm$.
Let G is a point on EC then $FE=EG$.
Join G and D and G and B, D and F.
BGDF is a parallelogram.
$BF=GD=5cm.$
$GD\parallel AF$ then $AF=10cm.$
Now $BA=BF+AF=5+10=15cm.$