Question

BD is a median of a triangle ABC. F is a point on AB such that CF intersects BD at E and $BE=ED$. If $BF=5cm$. BA is equal to:

• A. 10
• B. 12
• C. 15
• D. 17

Answer 1

The correct option is C 15

In a triangle ABC, BD is a median of a triangle.

And F is a point on AB such that CF intersects BD at E.
Also given $BE=ED,BF=5cm$.
Let G is a point on EC then $FE=EG$.
Join G and D and G and B, D and F.
∴ $BGDF$ is a parallelogram.
$BF=GD=5cm$
$GD||AF$ then $AF=10cm$
Now, $BA=BF+AF=5+10=15cm$