Be2 C -H2O - BeOH2 -X CaC2- H2 O - CaOH2 -YIn the above given reactions- X and Y are respectively -

The correct option is C CH_4 , C_2 H_2 Balanced reactions are: Be_2 C +4H_2O → 2Be(OH)_2 +CH_4 CaC_2+ 2H_2 O → Ca(OH)_2 +C_2H_2 So, X a ...

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Byju's Answer

Standard XII

Chemistry

Chemical Properties of Ethers

Be2 C +H2O → ...

Question

$B e_{2} C + H_{2} O \to B e (O H)_{2} + X$
$C a C_{2} + H_{2} O \to C a (O H)_{2} + Y$
In the above given reactions, $X$ and $Y$ are respectively :

C H_{4}

C H_{4}

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C H_{4}

C_{2} H_{6}

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C H_{4}

C_{2} H_{2}

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C_{2} H_{2}

C H_{4}

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Solution

The correct option is C $C H_{4}$ , $C_{2} H_{2}$
Balanced reactions are:
$B e_{2} C + 4 H_{2} O \to 2 B e (O H)_{2} + C H_{4}$
$C a C_{2} + 2 H_{2} O \to C a (O H)_{2} + C_{2} H_{2}$
So, $X$ and $Y$ are methane and acetylene respectively.

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Similar questions

B e_{2} C + H_{2} O \to B e (O H)_{2} + x

C a C_{2} + H_{2} O \to C a (O H)_{2} + y

then x and y are respectively:

$B e_{2} C + H_{2} O \to B e O + x$

$C a C_{2} + H_{2} O \to C a (O H)_{2} + y$

$M g_{2} C_{3} + H_{2} O \to M g (O H)_{2} + z$ .

$x, y$ & $z$ are respectively

C a C_{2} + H_{2} O \to A H_{2} S O_{4} / H g S O_{4} - -------- \to B

.

Identify A and B in the given reaction

{B e}_{2} C + 4 H_{2} O ⟶ 2 X + {C H}_{4}

X + 2 O H ⟶ Y

(X) and (Y) formed in the above two reactions are :

100 ml of $C H_{4}$ and $C_{2} H_{2}$ were exploded with excess of $O_{2}$ . After explosion and cooling, the mixture was treated with KOH, where a reduction of 165 ml was observed. Therefore the composition of the mixture is -

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Be2C+H2O→Be(OH)2+XCaC2+H2O→Ca(OH)2+YIn the above given reactions, X and Y are respectively :

The correct option is C CH4, C2H2Balanced reactions are:Be2C+4H2O→2Be(OH)2+CH4CaC2+2H2O→Ca(OH)2+C2H2So, X and Y are methane and acetylene respectively.

$B e_{2} C + H_{2} O \to B e (O H)_{2} + X$
$C a C_{2} + H_{2} O \to C a (O H)_{2} + Y$
In the above given reactions, $X$ and $Y$ are respectively :

The correct option is C $C H_{4}$ , $C_{2} H_{2}$
Balanced reactions are:
$B e_{2} C + 4 H_{2} O \to 2 B e (O H)_{2} + C H_{4}$
$C a C_{2} + 2 H_{2} O \to C a (O H)_{2} + C_{2} H_{2}$
So, $X$ and $Y$ are methane and acetylene respectively.