$B e^{2 +}$ is isoelectronic with which of the following ions?

H^{+}

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L i^{+}

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N a^{+}

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M g^{2 +}

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Solution

The correct option is B $L i^{+}$
$B e^{2 +}$ is isoelectronic with $L i^{+}$ .

Both contain 2 electrons.

They have an electronic configuration $B e^{2} = 1 s^{2} = L i^{+}$ .

This is equal to the electronic configuration of He.

Hence, the correct option is $B$

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