Be 2 C - H 2 O - Be OH 2- xCaC 2- H 2 O - Ca OH 2- ythen x and y are respectively-A- CH 4- CH 4B- CH 4- C 2 H 6C- CH 4- C 2 H 2D- C 2 H 2- CH 4

The correct option is C CH_4, C_2H_2Be_2C + 4H_2O →(x)CH_4 + 2Be(OH)_2 CaC_2 + 2H_2O → Ca(OH)_2 + (y)C_2H_2 nbsp; ...

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Synthesis by Reduction of Nitriles

Be 2 C + H 2 ...

Question

$B e_{2} C + H_{2} O \to B e (O H)_{2} + x$
$C a C_{2} + H_{2} O \to C a (O H)_{2} + y$
then x and y are respectively:

C H_{4}, C H_{4}

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C H_{4}, C_{2} H_{6}

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C H_{4}, C_{2} H_{2}

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C_{2} H_{2}, C H_{4}

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