Be $_{4}^{7}$ captures a K electron into its nucleus. What is the atomic number and atomic mass of the nuclide formed?

3, 7

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

4, 8

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3, 8

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4, 7

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D 3, 7
During K electron capture, the atomic number decreases by 1 and the mass number remains unchanged.
The balanced reaction is Be $_{4}^{7}$ + e $_{- 1}^{0}$ $\to$ Li $_{3}^{7}$ .
So, for the nuclide formed, atomic number = 3 and mass number = 7.

Suggest Corrections

Similar questions

Q. Be

_{4}^{7}

captures a K electron into its nucleus. What is the mass number and atomic number of the nuclide formed?

_{4}^{7} B e

captures a

K

-electron into its nucleus. What will be the mass number of resulting nuclide?

An atomic nucleus A is composed of 84 protons and 128 neutrons.

The atomic nucleus A emits an alpha particle and is transformed into nucleus B. The atomic nucleus B emits a $β$ - particle and is transformed into a nucleus C. What is the composition of atomic nucleus C?

Q. Assertion :

_{56}^{133} B a + e^{-} ⟶

_{55}^{133} C s + X

-ray.
It is an example of

K

-electron capture. Reason: Atomic number of daughter nuclide decreases by one unit in

K

-electron capture.

Q. An atomic nucleus A is composed of

84

protons and

128

neutrons. The nucleus A emits

α

-particle and is transformed into a nucleus B. What is the composition of B ?

Join BYJU'S Learning Program

Be74 captures a K electron into its nucleus. What is the atomic number and atomic mass of the nuclide formed?

The correct option is D 3, 7During K electron capture, the atomic number decreases by 1 and the mass number remains unchanged.The balanced reaction is Be74 + e0−1 → Li73.So, for the nuclide formed, atomic number = 3 and mass number = 7.

Be $_{4}^{7}$ captures a K electron into its nucleus. What is the atomic number and atomic mass of the nuclide formed?

The correct option is D 3, 7
During K electron capture, the atomic number decreases by 1 and the mass number remains unchanged.
The balanced reaction is Be $_{4}^{7}$ + e $_{- 1}^{0}$ $\to$ Li $_{3}^{7}$ .
So, for the nuclide formed, atomic number = 3 and mass number = 7.