Be $_{4}^{7}$ captures a K electron into its nucleus. What is the mass number and atomic number of the nuclide formed?

3, 7

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4, 8

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3, 8

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4, 7

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Solution

The correct option is A 3, 7
Be $_{4}^{7}$ + e $_{- 1}^{0}$ $\to$ Li $_{3}^{7}$
So, atomic number = 3, mass number = 7

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Similar questions

Q. Be

_{4}^{7}

captures a K electron into its nucleus. What is the atomic number and atomic mass of the nuclide formed?

_{4}^{7} B e

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Q. Assertion :

_{56}^{133} B a + e^{-} ⟶

_{55}^{133} C s + X

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It is an example of

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An atomic nucleus A is composed of 84 protons and 128 neutrons.

The atomic nucleus A emits an alpha particle and is transformed into nucleus B. The atomic nucleus B emits a $β$ - particle and is transformed into a nucleus C. What is the composition of atomic nucleus C?

Q. An atom has 7 electrons in its M - shell and contains 18 neutrons in its nucleus. What is its mass number

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Be74 captures a K electron into its nucleus. What is the mass number and atomic number of the nuclide formed?

The correct option is A 3, 7Be74 + e0−1 → Li73So, atomic number = 3, mass number = 7

Be $_{4}^{7}$ captures a K electron into its nucleus. What is the mass number and atomic number of the nuclide formed?

The correct option is A 3, 7
Be $_{4}^{7}$ + e $_{- 1}^{0}$ $\to$ Li $_{3}^{7}$
So, atomic number = 3, mass number = 7