BE and CF are 2 equal altitudes of $△$ using congruence rule.Then $△ A B C$ is

Isosceles Triangle

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Equilateral Triangle

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Scalane Triangle

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None of these

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Solution

The correct option is A Isosceles Triangle
Area of triangle= $\frac{1}{2} \times$ base $\times$ corresponding height
Area of $△ A B C = \frac{1}{2} \times A B \times C F = \frac{1}{2} \times A C \times B E$
$(∵ B E = C F)$
$⟹ A r e a = \frac{1}{2} \times A B \times B E = \frac{1}{2} \times A C \times B E$
$⟹ \frac{1}{2} \times A B = \frac{1}{2} \times A C$
$⟹ A B = A C$
$∴ △ A B C i s i s o s c l e s t r i a n g l e .$

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