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Question

Beakers $$A,\ B$$ and $$C$$ contain zinc sulphate, silver nitrate and iron (II) sulphate solutions respectively. Copper pieces are added to each beaker. The blue colour will appear in case of:


A
beaker A
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B
beaker B
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C
beaker C
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D
all the beakers
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Solution

The correct option is A beaker $$B$$
Given that, 
Beaker, 
$$A = ZnSO_4$$
$$B = AgNO_3$$
$$C = FeSO_4$$

When copper pieces added in each beaker, only less reactive solution will be displaced by $$Cu$$.
According to reactivity series $$Cu$$ is more reactive than silver and less reactive than $$Zn$$ and $$Fe$$.

$$2Cu + \underset{Solution}{\underset{Beaker (B)}{2AgNO_3}} \rightarrow \underset{Blue \ colour}{Cu(NO_3)_2} + 2Ag$$

Chemistry

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