Beakers $A, B$ and $C$ contain zinc sulphate, silver nitrate and iron (II) sulphate solutions respectively. Copper pieces are added to each beaker. The blue colour will appear in case of:

beaker

A

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beaker

B

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beaker

C

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all the beakers

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Solution

The correct option is A beaker $B$
Given that,
Beaker,
$A = Z n S O_{4}$
$B = A g N O_{3}$
$C = F e S O_{4}$

When copper pieces added in each beaker, only less reactive solution will be displaced by $C u$ .
According to reactivity series $C u$ is more reactive than silver and less reactive than $Z n$ and $F e$ .

$2 C u + 2 A g N O_{3} B e a k e r (B) S o l u t i o n \to C u (N O_{3})_{2} B l u e c o l o u r + 2 A g$

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Beakers A, B and C contain zinc sulphate, silver nitrate and iron (II) sulphate solutions respectively. Copper pieces are added to each beaker. The blue colour will appear in case of:

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