Beats are produced due to the superposition of two progressive notes of same amplitude. Maximum intensity is n times the intensity of either note. The value of n is :

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Solution

The correct option is D 4
Given $: \frac{I_{m a x}}{I} = n$
$A_{1} = A_{2}$
$\frac{I_{m a x}}{I} = \frac{(A_{1} + A_{2})^{2}}{(A_{1})^{2}}$
$n = \frac{(2 A_{1})^{2}}{(A_{1})^{2}}$ $= \frac{4}{1}$

$S o, n = 4$

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Beats are produced due to the superposition of two progressive notes of same amplitude. Maximum intensity is n times the intensity of either note. The value of n is :

The correct option is D 4Given :ImaxI=nA1=A2ImaxI=(A1+A2)2(A1)2n=(2A1)2(A1)2=41So,n=4

The correct option is D 4
Given $: \frac{I_{m a x}}{I} = n$
$A_{1} = A_{2}$
$\frac{I_{m a x}}{I} = \frac{(A_{1} + A_{2})^{2}}{(A_{1})^{2}}$
$n = \frac{(2 A_{1})^{2}}{(A_{1})^{2}}$ $= \frac{4}{1}$

$S o, n = 4$