Question

$BeC{l}_2$ can exist in monomeric form, dimeric form as well as polymeric form. Identify the hybridisation of $Be$ in polymeric $BeC{l}_2$

• A. $sp$
• B. $s{p}^2$
• C. $s{p}^3$
• D. $s{p}^{3}d$

Answer 1

The correct option is C $s{p}^3$

In vapour state, $BeC{l}_2$ exists as a linear molecule, $i.e.$ each $Be$ is bonded to two $Cl$ atoms and $Be$ is $sp$ hybridised. Whereas in the solid state, $BeC{l}_2$ exists as a polymer and each $Be$ is bonded to two $Cl$ atoms by covalent bond and two $Cl$ atoms by coordinate bond. $Be$ atom in solid $BeC{l}_2$ is $s{p}^3$ hybridised.

So in polymer it is $s{p}^3$ hybridization, hence option C is the correct answer.