$B e F_{2}$ is formed by the decomposition of:

B e C l_{2}

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(N H_{4})_{2} B e F_{4}

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B e C O_{3}

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None of the above

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Solution

The correct option is B $(N H_{4})_{2} B e F_{4}$
$B e F_{2}$ is best prepared by decompostion of $(N H_{4})_{2} B e F_{4}$

$(N H_{4})_{2} B e F_{4} ⟶ 2 N H_{4} F + B e F_{2}$

Theory
Reactivity towards halogen:
Group 2 elements combine with halogens at elevated temperature to form their corresponding halides
$M + X_{2} ⟶ M X_{2}$
(X= F,Cl ,Br,I)
$B e F_{2}$ is best formed by the thermal decomposition of $(N H_{4})_{2} B F_{4}$
$(N H_{4})_{2} B F_{4} ⟶ 2 N H_{4} F + B F_{2}$

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