Before a cricket match, the officials wanted to check the distance of the boundary from the centre of the pitch, given that the ground is circular in shape. The entire boundary length is 628 m. Also find its area in $m^{2}$ . Take $π = 3.14$ . [3 MARKS]

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Solution

Formula: 1 Mark
Radius: 1 Mark
Area: 1 Mark

Given that,
The entire length of the boundary is 628 m.
The perimeter of a cricket of radius r meters is $2 \times π \times r$ meters

Given perimeter of the ground = 628 m

r = $628 \div (2 \times π)$ =100 m
The distance of the boundary from the centre of the pitch is 100 m.
The area of a circle is $π \times (r)^{2}$

Area of the ground = $π \times (100)^{2}$

= 31400 $m^{2}$
The area of the ground is 31400 $m^{2}$ .

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Before a cricket match, the officials wanted to check the distance of the boundary from the centre of the pitch, given that the ground is circular in shape. The entire boundary length is 628 m. Also find its area in m2 . Take π=3.14. [3 MARKS]

Before a cricket match, the officials wanted to check the distance of the boundary from the centre of the pitch, given that the ground is circular in shape. The entire boundary length is 628 m. Also find its area in $m^{2}$ . Take $π = 3.14$ . [3 MARKS]