Before a cricket match the officials wanted to check the distance of the boundary from the centre of the pitch, given that the ground is circular in shape. The entire boundary length is 628 m. Find its area in $m^{2}$ . Take $π$ =3.14. [3 MARKS]

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Solution

Process : 2 Marks
Result : 1 Mark

The perimeter of a circket of radius r meters is 2r meters

Given perimeter of the ground = 628 m

r = 100 m

Area of the ground = $π \times (100)^{2}$

= 31400

=31400 $m^{2}$

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Before a cricket match the officials wanted to check the distance of the boundary from the centre of the pitch, given that the ground is circular in shape. The entire boundary length is 628 m. Find its area in m2 . Take π=3.14. [3 MARKS]

Process : 2 Marks Result : 1 Mark The perimeter of a circket of radius r meters is 2r meters Given perimeter of the ground = 628 m r = 100 m Area of the ground = π×(100)2 = 31400 =31400 m2

Before a cricket match the officials wanted to check the distance of the boundary from the centre of the pitch, given that the ground is circular in shape. The entire boundary length is 628 m. Find its area in $m^{2}$ . Take $π$ =3.14. [3 MARKS]

Process : 2 Marks
Result : 1 Mark

The perimeter of a circket of radius r meters is 2r meters

Given perimeter of the ground = 628 m

r = 100 m

Area of the ground = $π \times (100)^{2}$

= 31400

=31400 $m^{2}$