The correct option is B 27.69
The given table can be re-written as follows:
Marks0−1010−2020−3030−4040−50Frequency551389Cumulative Frequency510233140
In the above distribution the total number of observations is 40. Hence, n = 40.
n2=20.
The cumulative frequency that is greater than 20 but closest to 20 is 23. The class corresponding to this frequency is 20-30. This is the median class.
Using Median = l+(n2−cff)×h
Where l is lower class limit of median class.
n is the total number of observations.
cf is the cumulative frequency of the class preceding the median class.
f is the frequency of the median class and h is the class size.
⟹Median=20+20−1013×10
⟹Median=20+7.69
∴Median=27.69