-beginarray -c-c-c-c-c-c-Whine- Column 1 - - Column 2 - - Column3llthlineI - -ve - i - -ve - P - inftylllhline II- infty - ii - 0 -Q - -ve lllhline III- 0 - iii - infty - R - -velllhline IV- -ve - iv - -ve - S - 0 Nllhline e n d array The correct set for boiling of water at 110- C -A- IV IV QB- IV iv SC- II iv PD- I ii R

The correct option is A (IV) (IV) (Q)Boiling of water at 110^∘C is spontaneous i.e. Δ G ve Its an endothermic process ⇒Δ H =+ve. and entropy is increasing ...

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Byju's Answer

Standard XII

Chemistry

Entropy Change in Irreversible Process

いbeginarray |...

Question

$\begin{matrix} C o l u m n s 1 r e p r e s e n t s Δ G, & C o l u m n 2 Δ H & a n d C o l u m n 3 Δ S . C o l u m n 1 & C o l u m n 2 & C o l u m n 3 (I) & + v e & (i) & - v e & (P) & \infty (I I) & \infty & (i i) & 0 & (Q) & + v e (I I I) & 0 & (i i i) & \infty & (R) & - v e (I V) & - v e & (i v) & + v e & (S) & 0 \end{matrix}$
The correct set for boiling of water at $110^{\circ} C$ ?

(IV) (IV) (Q)

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(II) (iv) (P)

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(I) (ii) (R)

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(IV) (iv) (S)

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Solution

The correct option is A (IV) (IV) (Q)
Boiling of water at $110^{\circ} C$ is spontaneous i.e. $Δ G - v e$
Its an endothermic process $\Rightarrow Δ H = + v e .$
and entropy is increasing $\Rightarrow Δ s = + v e .$

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Similar questions

\begin{matrix} Δ G & Δ H & Δ S (I) & + v e & (i) & - v e & (P) & \infty (I I) & \infty & (i i) & 0 & (Q) & + v e (I I I) & 0 & (i i i) & \infty & (R) & - v e (i v) & - v e & (i v) & + v e & (S) & 0 \end{matrix}

The correct set for melting of ice at

- 15^{\circ} C

is:

\begin{matrix} C o l u m n s 1 r e p r e s e n t s Δ G, & C o l u m n 2 Δ H & a n d C o l u m n 3 Δ S . C o l u m n 1 & C o l u m n 2 & C o l u m n 3 (I) & + v e & (i) & - v e & (P) & \infty (I I) & \infty & (i i) & 0 & (Q) & + v e (I I I) & 0 & (i i i) & \infty & (R) & - v e (I V) & - v e & (i v) & + v e & (S) & 0 \end{matrix}

The correct set for Haber’s process is (when equilibrium is just to be reached)

$\begin{matrix} C o l u m n I & C o l u m n 2 & C o l u m n 3 (I) & f (x) = t a n (2 t a n^{- 1} \sqrt{\frac{\sqrt{1 + \sqrt{x}} - 1}{\sqrt{1 + \sqrt{x}} + 1}}) & (i) & \int f (x) d x = \frac{4}{3} x^{\frac{3}{4}} + C & (P) & \int_{0}^{1} f (x) d x = \frac{4}{3} (I I) & f (x) = c o t (2 t a n^{- 1} \sqrt{\frac{\sqrt{1 + \sqrt{x}} - \sqrt[4]{x}}{\sqrt{1 + \sqrt{x}} + \sqrt[4]{x}}}) & (i i) & \int f (x) d x = \frac{4}{5} x^{\frac{5}{4}} + C & (Q) & \int_{0}^{1} f (x) d x = \frac{4}{5} (I I I) & f (x) ⎛ ⎜ ⎝ \frac{1 - t a n (\frac{1}{2} s i n^{- 1} (\frac{1 - \sqrt{x}}{1 + \sqrt{x}}))}{1 + t a n (\frac{1}{2} s i n^{- 1} (\frac{1 - \sqrt{x}}{1 + \sqrt{x}}))} ⎞ ⎟ ⎠ & (i i i) & \int f (x) d x = \frac{2}{3} x^{\frac{3}{4}} + C & (R) & \int_{0}^{1} f (x) d x = \frac{2}{3} (I V) & f (x) = \sqrt{x} t a n (2 t a n^{- 1} (\frac{\sqrt{\sqrt{1 + \sqrt{x} + 1}} - \sqrt{\sqrt{1 + \sqrt{x} - 1}}}{\sqrt{\sqrt{1 + \sqrt{x} + 1}} + \sqrt{\sqrt{1 + \sqrt{x} - 1}}})) & (i v) & \int f (x) d x = \frac{2}{5} x^{\frac{5}{4}} + C & (S) & \int_{0}^{1} f (x) d x = \frac{2}{5} \end{matrix}$

Which of the following options is only correct combination?

Q. Match the species in Column I with the shape in Column II.

\begin{matrix} Column I & Column II i . & O S F_{2} & p . & Tetrahedral i i . & O_{2} S F_{2} & q . & Linear i i i . & X e F_{4} & r . & Square planar i v . & C l O_{4}^{-} & s . & Trigonal pyramidal v . & I_{3}^{-} & t . & See - saw \end{matrix}

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Columns 1 represents ΔG,Column 2ΔHand Column 3ΔS.Column1Column2Column3(I)+ve(i)−ve(P)∞(II)∞(ii)0(Q)+ve(III)0(iii)∞(R)−ve(IV)−ve(iv)+ve(S)0 The correct set for boiling of water at 110∘C?

The correct option is A (IV) (IV) (Q)Boiling of water at 110∘C is spontaneous i.e. ΔG−ve Its an endothermic process ⇒ΔH=+ve. and entropy is increasing ⇒Δs=+ve.

The correct option is A (IV) (IV) (Q)
Boiling of water at $110^{\circ} C$ is spontaneous i.e. $Δ G - v e$
Its an endothermic process $\Rightarrow Δ H = + v e .$
and entropy is increasing $\Rightarrow Δ s = + v e .$