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Question

Xi39101213fi34524
Mean deviation about median for this grouped frequency distribution is .

A
2.21
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B
2.27
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C
2.9
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D
5
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Solution

The correct option is B 2.27

The observations are already in ascending order.

Let's calculate the cumulative frequencies

Xi39101213fi34524c.f.37121418

Median of the observations would be average of 9th and 10th readings =9th term+10th term2=10+102=10

Let's calculate fi|xiM| for given observations.

|xiM|71023fi34524fi|xiM|2140412

Mean deviation about the median, M.D(M)=ni=1fi|xiM|ni=1fi

=21+4+0+4+1218

4118=2.28


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