$\begin{matrix} C i t i e s & S h i m l a & B a n g a l o r e & D e l h i & M u m b a i p i n N / m^{2} & 1.01 \times 10^{5} & 1.2 \times 10^{5} & 1.02 \times 10^{5} & 1.21 \times 10^{5} \end{matrix}$

Consider the above data and mark the place at which liquid will boil first.

(a) Shimla (b) Bangalore (c) Delhi (d) Mumbai

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Solution

Answer: (a) Shimla

Shimla has the lowest atmospheric pressure among all the four cities. Thus, at Shimla liquid will boil first because lower the atmospheric pressure, lower is the boiling point.

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\begin{matrix} Cities & Shimla & Bangalore & Delhi & Mumbai p {in N/m}^{2} & 1.01 \times 10^{5} & 1.2 \times 10^{5} & 1.02 \times 10^{5} & 1.21 \times 10^{5} \end{matrix}

\begin{matrix} C i t i e s & M u s s o r i e & B a n g a l o r e & D e l h i & G o a P i n (N / m^{2}) & 1.01 \times 10^{5} & 1.2 \times 10^{5} & 1.02 \times 10^{5} & 1.21 \times 10^{5} \end{matrix}

\begin{matrix} C i t i e s & M u s s o r i e & B a n g a l o r e & D e l h i & G o a P i n (N / m^{2}) & 1.01 \times 10^{5} & 1.2 \times 10^{5} & 1.02 \times 10^{5} & 1.21 \times 10^{5} \end{matrix}

Cities	Shimla	Bangalore	Delhi	Mumbai
$p$ in $N / m^{2}$	$1.01 \times 10^{5}$	$1.2 \times 10^{5}$	$1.02 \times 10^{5}$	$1.21 \times 10^{5}$

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