Question 13
$\begin{matrix} B l o o d g r o u p & N u m b e r o f s t u d e n t s A & 9 B & 6 A B & 3 O & 12 T o t a l & 30 \end{matrix}$
The above frequency distribution table represents the blood groups of 30 students of a class. Use this table to determine the probability that a student of this class, selected at random, has blood group AB.

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Solution

Total number of students = 30
Number of students having blood group AB= 3

$P (s t u d e n t s h a v i n g b l o o d g r o u p A B) = \frac{N u m b e r o f s t u d e n t s h a v i n g b l o o d g r o u p A B}{T o t a l n u m b e r o f s t u d e n t s}$
Hence, required probability, $P = \frac{3}{30} = \frac{1}{10}$

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Question 13
$\begin{matrix} Blood group & Number of students A & 9 B & 6 AB & 3 O & 12 Total & 30 \end{matrix}$
The above frequency distribution table represents the blood groups of 30 students of a class. Use this table to determine the probability that a student of this class, selected at random, has blood group AB.

\begin{matrix} Blood group & Number of students A & 9 B & 6 AB & 3 O & 12 Total & 30 \end{matrix}

The above frequency distribution table represents the blood groups of 30 students of a class. Use this table to determine the probability that a student of this class, selected at random, has blood group AB.

Blood group	Number of students
A	9
B	6
AB	3
O	12
Total	30

Q. The below frequency distribution table represents the blood groups of

30

students of a class. Use this table to determine the probability that a student of this class, selected at random, has blood group

A B

Blood group	Number of students
A	9
B	6
AB	3
O	12
Total	30

Q. You were to prepare a frequency distribution table regarding the blood groups of

30

students of a class, Use this table to determine the probability that a student of this clss, selected at random, has blood group

A B

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Question 13 Blood groupNumber of studentsA9B6AB3O12Total30 The above frequency distribution table represents the blood groups of 30 students of a class. Use this table to determine the probability that a student of this class, selected at random, has blood group AB.

Total number of students = 30 Number of students having blood group AB= 3 P(students having blood group AB)=Number of students having blood group ABTotal number of students Hence, required probability, P=330=110